Base | Representation |
---|---|
bin | 10010111010110100101… |
… | …110001001100100111000 |
3 | 11121021211001022202010012 |
4 | 102322310232021210320 |
5 | 132300112200320440 |
6 | 2433132510441052 |
7 | 162633663453242 |
oct | 22726456114470 |
9 | 4537731282105 |
10 | 1300112120120 |
11 | 461413441750 |
12 | 18bb78b03188 |
13 | 957a53c27c8 |
14 | 46cd6413092 |
15 | 23c43bc0e65 |
hex | 12eb4b89938 |
1300112120120 has 128 divisors (see below), whose sum is σ = 3208214520000. Its totient is φ = 470251008000.
The previous prime is 1300112120117. The next prime is 1300112120123. The reversal of 1300112120120 is 210212110031.
It is an interprime number because it is at equal distance from previous prime (1300112120117) and next prime (1300112120123).
It is a junction number, because it is equal to n+sod(n) for n = 1300112120095 and 1300112120104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300112120123) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 73241006 + ... + 73258754.
Almost surely, 21300112120120 is an apocalyptic number.
1300112120120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1300112120120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1604107260000).
1300112120120 is an abundant number, since it is smaller than the sum of its proper divisors (1908102399880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300112120120 is a wasteful number, since it uses less digits than its factorization.
1300112120120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18649 (or 18645 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1300112120120 its reverse (210212110031), we get a palindrome (1510324230151).
It can be divided in two parts, 13001 and 12120120, that added together give a palindrome (12133121).
The spelling of 1300112120120 in words is "one trillion, three hundred billion, one hundred twelve million, one hundred twenty thousand, one hundred twenty".
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