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1300112120120 = 2351127760117749
BaseRepresentation
bin10010111010110100101…
…110001001100100111000
311121021211001022202010012
4102322310232021210320
5132300112200320440
62433132510441052
7162633663453242
oct22726456114470
94537731282105
101300112120120
11461413441750
1218bb78b03188
13957a53c27c8
1446cd6413092
1523c43bc0e65
hex12eb4b89938

1300112120120 has 128 divisors (see below), whose sum is σ = 3208214520000. Its totient is φ = 470251008000.

The previous prime is 1300112120117. The next prime is 1300112120123. The reversal of 1300112120120 is 210212110031.

It is an interprime number because it is at equal distance from previous prime (1300112120117) and next prime (1300112120123).

It is a junction number, because it is equal to n+sod(n) for n = 1300112120095 and 1300112120104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300112120123) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 73241006 + ... + 73258754.

Almost surely, 21300112120120 is an apocalyptic number.

1300112120120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300112120120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1604107260000).

1300112120120 is an abundant number, since it is smaller than the sum of its proper divisors (1908102399880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300112120120 is a wasteful number, since it uses less digits than its factorization.

1300112120120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18649 (or 18645 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 1300112120120 its reverse (210212110031), we get a palindrome (1510324230151).

It can be divided in two parts, 13001 and 12120120, that added together give a palindrome (12133121).

The spelling of 1300112120120 in words is "one trillion, three hundred billion, one hundred twelve million, one hundred twenty thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 11 20 22 40 44 55 88 110 220 277 440 554 601 1108 1202 1385 2216 2404 2770 3005 3047 4808 5540 6010 6094 6611 11080 12020 12188 13222 15235 17749 24040 24376 26444 30470 33055 35498 52888 60940 66110 70996 88745 121880 132220 141992 166477 177490 195239 264440 332954 354980 390478 665908 709960 780956 832385 976195 1331816 1561912 1664770 1831247 1952390 3329540 3662494 3904780 4916473 6659080 7324988 7809560 9156235 9832946 10667149 14649976 18312470 19665892 21334298 24582365 36624940 39331784 42668596 49164730 53335745 54081203 73249880 85337192 98329460 106671490 108162406 117338639 196658920 213342980 216324812 234677278 270406015 426685960 432649624 469354556 540812030 586693195 938709112 1081624060 1173386390 2163248120 2346772780 2954800273 4693545560 5909600546 11819201092 14774001365 23638402184 29548002730 32502803003 59096005460 65005606006 118192010920 130011212012 162514015015 260022424024 325028030030 650056060060 1300112120120