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13001123111220 = 22325317227850037
BaseRepresentation
bin1011110100110000111101…
…0100110010000100110100
31201000220011121211111020100
42331030033110302010310
53201002300004024340
643352344500434100
72511204644032206
oct275141724620464
951026147744210
1013001123111220
11416282206a892
12155b8559a8930
1373400156b67a
1432d38725c776
151782c8085830
hexbd30f532134

13001123111220 has 72 divisors (see below), whose sum is σ = 39561146397864. Its totient is φ = 3456029346048.

The previous prime is 13001123111213. The next prime is 13001123111293. The reversal of 13001123111220 is 2211132110031.

13001123111220 is a `hidden beast` number, since 1 + 300 + 1 + 1 + 231 + 112 + 20 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 151436165904 + 12849686945316 = 389148^2 + 3584646^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13001123111193 and 13001123111202.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 113867959 + ... + 113982078.

It is an arithmetic number, because the mean of its divisors is an integer number (549460366637).

Almost surely, 213001123111220 is an apocalyptic number.

13001123111220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13001123111220 is an abundant number, since it is smaller than the sum of its proper divisors (26560023286644).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13001123111220 is a wasteful number, since it uses less digits than its factorization.

13001123111220 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 227850369 (or 227850364 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 13001123111220 its reverse (2211132110031), we get a palindrome (15212255221251).

The spelling of 13001123111220 in words is "thirteen trillion, one billion, one hundred twenty-three million, one hundred eleven thousand, two hundred twenty".

Divisors: 1 2 3 4 5 6 9 10 12 15 18 20 30 36 45 60 90 180 317 634 951 1268 1585 1902 2853 3170 3804 4755 5706 6340 9510 11412 14265 19020 28530 57060 227850037 455700074 683550111 911400148 1139250185 1367100222 2050650333 2278500370 2734200444 3417750555 4101300666 4557000740 6835501110 8202601332 10253251665 13671002220 20506503330 41013006660 72228461729 144456923458 216685385187 288913846916 361142308645 433370770374 650056155561 722284617290 866741540748 1083426925935 1300112311122 1444569234580 2166853851870 2600224622244 3250280777805 4333707703740 6500561555610 13001123111220