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130011310212010 = 2513199245274971
BaseRepresentation
bin11101100011111010011101…
…111101100100001110101010
3122001022221220202011120212221
4131203322131331210032222
5114020101130403241020
61140302212115024254
736246002316005503
oct3543723575441652
9561287822146787
10130011310212010
113847553a254987
12126b909089b08a
135771024844826
14241681c33dbaa
151006d5c4b26aa
hex763e9df643aa

130011310212010 has 16 divisors (see below), whose sum is σ = 235806773333472. Its totient is φ = 51607542984400.

The previous prime is 130011310211917. The next prime is 130011310212041. The reversal of 130011310212010 is 10212013110031.

It is a happy number.

It is a super-2 number, since 2×1300113102120102 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49622636176 + ... + 49622638795.

It is an arithmetic number, because the mean of its divisors is an integer number (14737923333342).

Almost surely, 2130011310212010 is an apocalyptic number.

130011310212010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

130011310212010 is a deficient number, since it is larger than the sum of its proper divisors (105795463121462).

130011310212010 is a wasteful number, since it uses less digits than its factorization.

130011310212010 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 99245275109.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 130011310212010 its reverse (10212013110031), we get a palindrome (140223323322041).

The spelling of 130011310212010 in words is "one hundred thirty trillion, eleven billion, three hundred ten million, two hundred twelve thousand, ten".

Divisors: 1 2 5 10 131 262 655 1310 99245274971 198490549942 496226374855 992452749710 13001131021201 26002262042402 65005655106005 130011310212010