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13001132301149 is a prime number
BaseRepresentation
bin1011110100110000111111…
…0111110101101101011101
31201000220012021010101110002
42331030033313311231131
53201002304332114044
643352345425424045
72511205115116046
oct275141767655535
951026167111402
1013001132301149
114162827277373
12155b858a9b025
137340034385b5
1432d3885718cd
151782c8c9d74e
hexbd30fdf5b5d

13001132301149 has 2 divisors, whose sum is σ = 13001132301150. Its totient is φ = 13001132301148.

The previous prime is 13001132301043. The next prime is 13001132301169. The reversal of 13001132301149 is 94110323110031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10238496055225 + 2762636245924 = 3199765^2 + 1662118^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13001132301149 is a prime.

It is a super-2 number, since 2×130011323011492 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13001132301169) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500566150574 + 6500566150575.

It is an arithmetic number, because the mean of its divisors is an integer number (6500566150575).

Almost surely, 213001132301149 is an apocalyptic number.

It is an amenable number.

13001132301149 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001132301149 is an equidigital number, since it uses as much as digits as its factorization.

13001132301149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 29.

The spelling of 13001132301149 in words is "thirteen trillion, one billion, one hundred thirty-two million, three hundred one thousand, one hundred forty-nine".