Base | Representation |
---|---|
bin | 10010111010110100111… |
… | …101001110000111110100 |
3 | 11121021211022202110120101 |
4 | 102322310331032013310 |
5 | 132300114203232100 |
6 | 2433133131243444 |
7 | 162634042156453 |
oct | 22726475160764 |
9 | 4537738673511 |
10 | 1300116070900 |
11 | 46141569aa59 |
12 | 18bb7a2a9584 |
13 | 957a6176b4a |
14 | 46cd6b60b9a |
15 | 23c4420186a |
hex | 12eb4f4e1f4 |
1300116070900 has 36 divisors (see below), whose sum is σ = 2833360301772. Its totient is φ = 517814460160.
The previous prime is 1300116070853. The next prime is 1300116070987. The reversal of 1300116070900 is 90706110031.
It can be written as a sum of positive squares in 6 ways, for example, as 210756282724 + 1089359788176 = 459082^2 + 1043724^2 .
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27876187 + ... + 27922786.
It is an arithmetic number, because the mean of its divisors is an integer number (78704452827).
Almost surely, 21300116070900 is an apocalyptic number.
1300116070900 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1300116070900 is an abundant number, since it is smaller than the sum of its proper divisors (1533244230872).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300116070900 is a wasteful number, since it uses less digits than its factorization.
1300116070900 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55799220 (or 55799213 counting only the distinct ones).
The product of its (nonzero) digits is 1134, while the sum is 28.
The spelling of 1300116070900 in words is "one trillion, three hundred billion, one hundred sixteen million, seventy thousand, nine hundred".
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