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1300120221230 = 25271947816117
BaseRepresentation
bin10010111010110101001…
…101000011011000101110
311121021211121120022202022
4102322311031003120232
5132300121234034410
62433133400230142
7162634122353525
oct22726515033056
94537747508668
101300120221230
11461417a75186
1218bb7b76b352
13957a6c9ac6c
1446cd75214bc
1523c44771455
hex12eb534362e

1300120221230 has 16 divisors (see below), whose sum is σ = 2341077137280. Its totient is φ = 519856813152.

The previous prime is 1300120221221. The next prime is 1300120221247. The reversal of 1300120221230 is 321220210031.

It is a super-2 number, since 2×13001202212302 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1300120221199 and 1300120221208.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23880869 + ... + 23935248.

It is an arithmetic number, because the mean of its divisors is an integer number (146317321080).

Almost surely, 21300120221230 is an apocalyptic number.

1300120221230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1300120221230 is a deficient number, since it is larger than the sum of its proper divisors (1040956916050).

1300120221230 is a wasteful number, since it uses less digits than its factorization.

1300120221230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47818843.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1300120221230 its reverse (321220210031), we get a palindrome (1621340431261).

The spelling of 1300120221230 in words is "one trillion, three hundred billion, one hundred twenty million, two hundred twenty-one thousand, two hundred thirty".

Divisors: 1 2 5 10 2719 5438 13595 27190 47816117 95632234 239080585 478161170 130012022123 260024044246 650060110615 1300120221230