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1300120221247 is a prime number
BaseRepresentation
bin10010111010110101001…
…101000011011000111111
311121021211121120022202221
4102322311031003120333
5132300121234034442
62433133400230211
7162634122353551
oct22726515033077
94537747508687
101300120221247
11461417a751a1
1218bb7b76b367
13957a6c9ac83
1446cd75214d1
1523c44771467
hex12eb534363f

1300120221247 has 2 divisors, whose sum is σ = 1300120221248. Its totient is φ = 1300120221246.

The previous prime is 1300120221221. The next prime is 1300120221251. The reversal of 1300120221247 is 7421220210031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1300120221247 - 231 = 1297972737599 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300120221217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650060110623 + 650060110624.

It is an arithmetic number, because the mean of its divisors is an integer number (650060110624).

Almost surely, 21300120221247 is an apocalyptic number.

1300120221247 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300120221247 is an equidigital number, since it uses as much as digits as its factorization.

1300120221247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 1300120221247 its reverse (7421220210031), we get a palindrome (8721340431278).

The spelling of 1300120221247 in words is "one trillion, three hundred billion, one hundred twenty million, two hundred twenty-one thousand, two hundred forty-seven".