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1300120963 is a prime number
BaseRepresentation
bin100110101111110…
…0100010110000011
310100121101222200021
41031133210112003
510130312332323
6333002034311
744134563061
oct11537442603
93317358607
101300120963
11607980139
123034a8997
1317947b05b
14c4953031
157921605d
hex4d7e4583

1300120963 has 2 divisors, whose sum is σ = 1300120964. Its totient is φ = 1300120962.

The previous prime is 1300120957. The next prime is 1300120979. The reversal of 1300120963 is 3690210031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1300120963 - 217 = 1299989891 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300120903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650060481 + 650060482.

It is an arithmetic number, because the mean of its divisors is an integer number (650060482).

Almost surely, 21300120963 is an apocalyptic number.

1300120963 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300120963 is an equidigital number, since it uses as much as digits as its factorization.

1300120963 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

The square root of 1300120963 is about 36057.1901706165. The cubic root of 1300120963 is about 1091.4267328208.

Adding to 1300120963 its reverse (3690210031), we get a palindrome (4990330994).

The spelling of 1300120963 in words is "one billion, three hundred million, one hundred twenty thousand, nine hundred sixty-three".