Base | Representation |
---|---|
bin | 10010111010110101011… |
… | …000001010001000100111 |
3 | 11121021211211001020012110 |
4 | 102322311120022020213 |
5 | 132300123010214310 |
6 | 2433133542452103 |
7 | 162634156200210 |
oct | 22726530121047 |
9 | 4537754036173 |
10 | 1300123132455 |
11 | 461419683454 |
12 | 18bb80734033 |
13 | 957a777a094 |
14 | 46cd7a7c407 |
15 | 23c44b48d20 |
hex | 12eb560a227 |
1300123132455 has 32 divisors (see below), whose sum is σ = 2432655650304. Its totient is φ = 580520094336.
The previous prime is 1300123132433. The next prime is 1300123132471. The reversal of 1300123132455 is 5542313210031.
It is not a de Polignac number, because 1300123132455 - 210 = 1300123131431 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 143973684 + ... + 143982713.
It is an arithmetic number, because the mean of its divisors is an integer number (76020489072).
Almost surely, 21300123132455 is an apocalyptic number.
1300123132455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1300123132455 is a deficient number, since it is larger than the sum of its proper divisors (1132532517849).
1300123132455 is a wasteful number, since it uses less digits than its factorization.
1300123132455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 287956455.
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 1300123132455 its reverse (5542313210031), we get a palindrome (6842436342486).
The spelling of 1300123132455 in words is "one trillion, three hundred billion, one hundred twenty-three million, one hundred thirty-two thousand, four hundred fifty-five".
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