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13001311157 is a prime number
BaseRepresentation
bin11000001101111000…
…00100001110110101
31020120002021001000212
430012330010032311
5203111313424112
65550035115205
7640120215152
oct140674041665
936502231025
1013001311157
1155719a055a
12262a142b05
1312c2740733
148b49cb229
15511610522
hex306f043b5

13001311157 has 2 divisors, whose sum is σ = 13001311158. Its totient is φ = 13001311156.

The previous prime is 13001311151. The next prime is 13001311229. The reversal of 13001311157 is 75111310031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11950643761 + 1050667396 = 109319^2 + 32414^2 .

It is a cyclic number.

It is not a de Polignac number, because 13001311157 - 26 = 13001311093 is a prime.

It is a super-2 number, since 2×130013111572 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13001311151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500655578 + 6500655579.

It is an arithmetic number, because the mean of its divisors is an integer number (6500655579).

Almost surely, 213001311157 is an apocalyptic number.

It is an amenable number.

13001311157 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001311157 is an equidigital number, since it uses as much as digits as its factorization.

13001311157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 315, while the sum is 23.

Adding to 13001311157 its reverse (75111310031), we get a palindrome (88112621188).

The spelling of 13001311157 in words is "thirteen billion, one million, three hundred eleven thousand, one hundred fifty-seven".