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130013131110000 = 2435426916110673
BaseRepresentation
bin11101100011111100001010…
…011111101111011001110000
3122001100010121122111210100020
4131203330022133233121300
5114020113343031010000
61140303112523123440
736246065406252135
oct3543741237573160
9561303548453306
10130013131110000
1138476294092556
12126b94ba673580
135771254b70968
1424169520d658c
151006e17297ba0
hex763f0a7ef670

130013131110000 has 200 divisors, whose sum is σ = 421259970471120. Its totient is φ = 34541280768000.

The previous prime is 130013131109999. The next prime is 130013131110007. The reversal of 130013131110000 is 11131310031.

It is a tau number, because it is divible by the number of its divisors (200).

It is a super-2 number, since 2×1300131311100002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130013131110007) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 14664 + ... + 16125336.

Almost surely, 2130013131110000 is an apocalyptic number.

130013131110000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130013131110000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (210629985235560).

130013131110000 is an abundant number, since it is smaller than the sum of its proper divisors (291246839361120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130013131110000 is a wasteful number, since it uses less digits than its factorization.

130013131110000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16110973 (or 16110952 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 130013131110000 its reverse (11131310031), we get a palindrome (130024262420031).

The spelling of 130013131110000 in words is "one hundred thirty trillion, thirteen billion, one hundred thirty-one million, one hundred ten thousand".