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13001319893 is a prime number
BaseRepresentation
bin11000001101111000…
…00110010111010101
31020120002021111000102
430012330012113111
5203111314214033
65550035223445
7640120252502
oct140674062725
936502244012
1013001319893
1155719a7081
12262a147b85
1312c27446c3
148b49d04a9
15511612de8
hex306f065d5

13001319893 has 2 divisors, whose sum is σ = 13001319894. Its totient is φ = 13001319892.

The previous prime is 13001319841. The next prime is 13001319907. The reversal of 13001319893 is 39891310031.

13001319893 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11835916849 + 1165403044 = 108793^2 + 34138^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13001319893 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13001319833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500659946 + 6500659947.

It is an arithmetic number, because the mean of its divisors is an integer number (6500659947).

Almost surely, 213001319893 is an apocalyptic number.

It is an amenable number.

13001319893 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001319893 is an equidigital number, since it uses as much as digits as its factorization.

13001319893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496, while the sum is 38.

The spelling of 13001319893 in words is "thirteen billion, one million, three hundred nineteen thousand, eight hundred ninety-three".