Search a number
-
+
1300166390093 is a prime number
BaseRepresentation
bin10010111010110111111…
…101001011000101001101
311121021221211102221112012
4102322313331023011031
5132300220043440333
62433142125551005
7162635222653604
oct22726775130515
94537854387465
101300166390093
1146144103956a
1218bb93115465
13957b371460c
1446cdd6dca3b
1523c48840e48
hex12eb7f4b14d

1300166390093 has 2 divisors, whose sum is σ = 1300166390094. Its totient is φ = 1300166390092.

The previous prime is 1300166389987. The next prime is 1300166390099. The reversal of 1300166390093 is 3900936610031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 814654266724 + 485512123369 = 902582^2 + 696787^2 .

It is an emirp because it is prime and its reverse (3900936610031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1300166390093 - 216 = 1300166324557 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1300166390093.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300166390099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650083195046 + 650083195047.

It is an arithmetic number, because the mean of its divisors is an integer number (650083195047).

Almost surely, 21300166390093 is an apocalyptic number.

It is an amenable number.

1300166390093 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300166390093 is an equidigital number, since it uses as much as digits as its factorization.

1300166390093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 78732, while the sum is 41.

The spelling of 1300166390093 in words is "one trillion, three hundred billion, one hundred sixty-six million, three hundred ninety thousand, ninety-three".