Base | Representation |
---|---|
bin | 111100100010111001… |
… | …1000011110111001111 |
3 | 110102121022121222021221 |
4 | 1321011303003313033 |
5 | 4112240112010301 |
6 | 135421432304211 |
7 | 12252006015355 |
oct | 1710563036717 |
9 | 412538558257 |
10 | 130020031951 |
11 | 50160a11467 |
12 | 21247542067 |
13 | c351099664 |
14 | 64160017d5 |
15 | 35ae9bdda1 |
hex | 1e45cc3dcf |
130020031951 has 2 divisors, whose sum is σ = 130020031952. Its totient is φ = 130020031950.
The previous prime is 130020031927. The next prime is 130020032059. The reversal of 130020031951 is 159130020031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130020031951 - 215 = 130019999183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130020031751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65010015975 + 65010015976.
It is an arithmetic number, because the mean of its divisors is an integer number (65010015976).
Almost surely, 2130020031951 is an apocalyptic number.
130020031951 is a deficient number, since it is larger than the sum of its proper divisors (1).
130020031951 is an equidigital number, since it uses as much as digits as its factorization.
130020031951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 25.
Adding to 130020031951 its reverse (159130020031), we get a palindrome (289150051982).
The spelling of 130020031951 in words is "one hundred thirty billion, twenty million, thirty-one thousand, nine hundred fifty-one".
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