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13002110099939 is a prime number
BaseRepresentation
bin1011110100110100101000…
…1001110110000111100011
31201000222201102000201020002
42331031022021312013203
53201011310141144224
643353030435210215
72511241260222302
oct275151211660743
951028642021202
1013002110099939
114163189207044
12155ba9044696b
1373412aba146c
1432d43c380439
15178334a469ae
hexbd34a2761e3

13002110099939 has 2 divisors, whose sum is σ = 13002110099940. Its totient is φ = 13002110099938.

The previous prime is 13002110099893. The next prime is 13002110099947. The reversal of 13002110099939 is 93999001120031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13002110099939 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13002110099893 and 13002110099902.

It is not a weakly prime, because it can be changed into another prime (13002110099959) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501055049969 + 6501055049970.

It is an arithmetic number, because the mean of its divisors is an integer number (6501055049970).

Almost surely, 213002110099939 is an apocalyptic number.

13002110099939 is a deficient number, since it is larger than the sum of its proper divisors (1).

13002110099939 is an equidigital number, since it uses as much as digits as its factorization.

13002110099939 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 118098, while the sum is 47.

The spelling of 13002110099939 in words is "thirteen trillion, two billion, one hundred ten million, ninety-nine thousand, nine hundred thirty-nine".