Base | Representation |
---|---|
bin | 1011110100110100101000… |
… | …1001110110000111110111 |
3 | 1201000222201102000201020211 |
4 | 2331031022021312013313 |
5 | 3201011310141144314 |
6 | 43353030435210251 |
7 | 2511241260222331 |
oct | 275151211660767 |
9 | 51028642021224 |
10 | 13002110099959 |
11 | 4163189207062 |
12 | 155ba90446987 |
13 | 73412aba1486 |
14 | 32d43c380451 |
15 | 178334a469c4 |
hex | bd34a2761f7 |
13002110099959 has 2 divisors, whose sum is σ = 13002110099960. Its totient is φ = 13002110099958.
The previous prime is 13002110099947. The next prime is 13002110099969. The reversal of 13002110099959 is 95999001120031.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (95999001120031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13002110099959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13002110099939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501055049979 + 6501055049980.
It is an arithmetic number, because the mean of its divisors is an integer number (6501055049980).
Almost surely, 213002110099959 is an apocalyptic number.
13002110099959 is a deficient number, since it is larger than the sum of its proper divisors (1).
13002110099959 is an equidigital number, since it uses as much as digits as its factorization.
13002110099959 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 196830, while the sum is 49.
The spelling of 13002110099959 in words is "thirteen trillion, two billion, one hundred ten million, ninety-nine thousand, nine hundred fifty-nine".
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