Base | Representation |
---|---|
bin | 1011110100110100101011… |
… | …0100100111010001100101 |
3 | 1201000222202012010022100220 |
4 | 2331031022310213101211 |
5 | 3201011321023430313 |
6 | 43353031515354553 |
7 | 2511241454425500 |
oct | 275151264472145 |
9 | 51028665108326 |
10 | 13002121311333 |
11 | 4163194574360 |
12 | 155ba94152a59 |
13 | 7341302c851b |
14 | 32d43da5c137 |
15 | 178335a0d823 |
hex | bd34ad27465 |
13002121311333 has 48 divisors (see below), whose sum is σ = 22000614405696. Its totient is φ = 6754122869760.
The previous prime is 13002121311323. The next prime is 13002121311337. The reversal of 13002121311333 is 33311312120031.
It is not a de Polignac number, because 13002121311333 - 28 = 13002121311077 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13002121311337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 55302135 + ... + 55536747.
It is an arithmetic number, because the mean of its divisors is an integer number (458346133452).
Almost surely, 213002121311333 is an apocalyptic number.
It is an amenable number.
13002121311333 is a deficient number, since it is larger than the sum of its proper divisors (8998493094363).
13002121311333 is a wasteful number, since it uses less digits than its factorization.
13002121311333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 268914 (or 268907 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 13002121311333 its reverse (33311312120031), we get a palindrome (46313433431364).
The spelling of 13002121311333 in words is "thirteen trillion, two billion, one hundred twenty-one million, three hundred eleven thousand, three hundred thirty-three".
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