1300213123119 has 64 divisors (see below), whose sum is σ = 2043312998400. Its totient is φ = 815433696000.

The previous prime is 1300213123109. The next prime is 1300213123123. The reversal of 1300213123119 is 9113213120031.

1300213123119 is a `hidden beast` number, since 1 + 30 + 0 + 2 + 1 + 312 + 311 + 9 = 666.

It is not a de Polignac number, because 1300213123119 - 2¹³ = 1300213114927 is a prime.

It is a super-2 number, since 2×1300213123119² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 1300213123092 and 1300213123101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300213123109) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 17997169 + ... + 18069269.

It is an arithmetic number, because the mean of its divisors is an integer number (31926765600).

Almost surely, 2^{1300213123119} is an apocalyptic number.

1300213123119 is a deficient number, since it is larger than the sum of its proper divisors (743099875281).

1300213123119 is a wasteful number, since it uses less digits than its factorization.

1300213123119 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72613 (or 72607 counting only the distinct ones).

The product of its (nonzero) digits is 972, while the sum is 27.

The spelling of 1300213123119 in words is "one trillion, three hundred billion, two hundred thirteen million, one hundred twenty-three thousand, one hundred nineteen".