130021434047311 has 2 divisors, whose sum is σ = 130021434047312. Its totient is φ = 130021434047310.

The previous prime is 130021434047279. The next prime is 130021434047317. The reversal of 130021434047311 is 113740434120031.

It is a strong prime.

It is an emirp because it is prime and its reverse (113740434120031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130021434047311 - 2⁵ = 130021434047279 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130021434047317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65010717023655 + 65010717023656.

It is an arithmetic number, because the mean of its divisors is an integer number (65010717023656).

Almost surely, 2^{130021434047311} is an apocalyptic number.

130021434047311 is a deficient number, since it is larger than the sum of its proper divisors (1).

130021434047311 is an equidigital number, since it uses as much as digits as its factorization.

130021434047311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 34.

Adding to 130021434047311 its reverse (113740434120031), we get a palindrome (243761868167342).

The spelling of 130021434047311 in words is "one hundred thirty trillion, twenty-one billion, four hundred thirty-four million, forty-seven thousand, three hundred eleven".