Base | Representation |
---|---|
bin | 111100100010111100… |
… | …1000110110010110011 |
3 | 110102121102121111022202 |
4 | 1321011321012302303 |
5 | 4112241013214234 |
6 | 135421530253415 |
7 | 12252025336103 |
oct | 1710571066263 |
9 | 412542544282 |
10 | 130021616819 |
11 | 501618a4176 |
12 | 21247b8726b |
13 | c351502b53 |
14 | 64162d5203 |
15 | 35aebd377e |
hex | 1e45e46cb3 |
130021616819 has 2 divisors, whose sum is σ = 130021616820. Its totient is φ = 130021616818.
The previous prime is 130021616761. The next prime is 130021616821. The reversal of 130021616819 is 918616120031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130021616819 - 224 = 130004839603 is a prime.
It is a super-2 number, since 2×1300216168192 (a number of 23 digits) contains 22 as substring.
Together with 130021616821, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (130021616869) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65010808409 + 65010808410.
It is an arithmetic number, because the mean of its divisors is an integer number (65010808410).
Almost surely, 2130021616819 is an apocalyptic number.
130021616819 is a deficient number, since it is larger than the sum of its proper divisors (1).
130021616819 is an equidigital number, since it uses as much as digits as its factorization.
130021616819 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 38.
The spelling of 130021616819 in words is "one hundred thirty billion, twenty-one million, six hundred sixteen thousand, eight hundred nineteen".
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