Base | Representation |
---|---|
bin | 11101100100000100011011… |
… | …110010001110000001110011 |
3 | 122001100222112111210002100212 |
4 | 131210010123302032001303 |
5 | 114020240034320220144 |
6 | 1140311142020134335 |
7 | 36246531434034452 |
oct | 3544043362160163 |
9 | 561328474702325 |
10 | 130022011101299 |
11 | 3847a030666439 |
12 | 126bb1785373ab |
13 | 577203b7c3095 |
14 | 24171555ccb99 |
15 | 1007286b6b49e |
hex | 76411bc8e073 |
130022011101299 has 2 divisors, whose sum is σ = 130022011101300. Its totient is φ = 130022011101298.
The previous prime is 130022011101223. The next prime is 130022011101377. The reversal of 130022011101299 is 992101110220031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130022011101299 is a prime.
It is not a weakly prime, because it can be changed into another prime (130022011101209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011005550649 + 65011005550650.
It is an arithmetic number, because the mean of its divisors is an integer number (65011005550650).
Almost surely, 2130022011101299 is an apocalyptic number.
130022011101299 is a deficient number, since it is larger than the sum of its proper divisors (1).
130022011101299 is an equidigital number, since it uses as much as digits as its factorization.
130022011101299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 32.
The spelling of 130022011101299 in words is "one hundred thirty trillion, twenty-two billion, eleven million, one hundred one thousand, two hundred ninety-nine".
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