Base | Representation |
---|---|
bin | 10010111010111011001… |
… | …010110111101000100100 |
3 | 11121022002120220110121120 |
4 | 102322323022313220210 |
5 | 132300322344441400 |
6 | 2433151333413540 |
7 | 162636446204613 |
oct | 22727312675044 |
9 | 4538076813546 |
10 | 1300220312100 |
11 | 461469518a06 |
12 | 18bba919a2b0 |
13 | 957c1943c28 |
14 | 46d0693787a |
15 | 23c4d442ca0 |
hex | 12ebb2b7a24 |
1300220312100 has 36 divisors (see below), whose sum is σ = 3761970770544. Its totient is φ = 346725416480.
The previous prime is 1300220312093. The next prime is 1300220312113. The reversal of 1300220312100 is 12130220031.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 1300220312100.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2167033554 + ... + 2167034153.
Almost surely, 21300220312100 is an apocalyptic number.
1300220312100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1300220312100 is an abundant number, since it is smaller than the sum of its proper divisors (2461750458444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300220312100 is a wasteful number, since it uses less digits than its factorization.
1300220312100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4334067724 (or 4334067717 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 1300220312100 its reverse (12130220031), we get a palindrome (1312350532131).
The spelling of 1300220312100 in words is "one trillion, three hundred billion, two hundred twenty million, three hundred twelve thousand, one hundred".
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