Base | Representation |
---|---|
bin | 10010111010111011010… |
… | …101101000000001001011 |
3 | 11121022002210012201102001 |
4 | 102322323111220001023 |
5 | 132300324110203343 |
6 | 2433151514051431 |
7 | 162636512160235 |
oct | 22727325500113 |
9 | 4538083181361 |
10 | 1300223131723 |
11 | 46147007437a |
12 | 18bbaa119b77 |
13 | 957c23c0449 |
14 | 46d0706d255 |
15 | 23c4d7ed44d |
hex | 12ebb56804b |
1300223131723 has 2 divisors, whose sum is σ = 1300223131724. Its totient is φ = 1300223131722.
The previous prime is 1300223131717. The next prime is 1300223131729. The reversal of 1300223131723 is 3271313220031.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (1300223131717) and next prime (1300223131729).
It is a cyclic number.
It is not a de Polignac number, because 1300223131723 - 29 = 1300223131211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1300223131691 and 1300223131700.
It is not a weakly prime, because it can be changed into another prime (1300223131729) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650111565861 + 650111565862.
It is an arithmetic number, because the mean of its divisors is an integer number (650111565862).
Almost surely, 21300223131723 is an apocalyptic number.
1300223131723 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300223131723 is an equidigital number, since it uses as much as digits as its factorization.
1300223131723 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536, while the sum is 28.
Adding to 1300223131723 its reverse (3271313220031), we get a palindrome (4571536351754).
The spelling of 1300223131723 in words is "one trillion, three hundred billion, two hundred twenty-three million, one hundred thirty-one thousand, seven hundred twenty-three".
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