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1300241144221 is a prime number
BaseRepresentation
bin10010111010111100011…
…010010101100110011101
311121022011001002211220121
4102322330122111212131
5132300343213103341
62433153400114541
7162640121240635
oct22727432254635
94538131084817
101300241144221
1146147a257438
1218bbb4165a51
13957c6059026
1446d095db6c5
1523c501aa4d1
hex12ebc69599d

1300241144221 has 2 divisors, whose sum is σ = 1300241144222. Its totient is φ = 1300241144220.

The previous prime is 1300241144207. The next prime is 1300241144261. The reversal of 1300241144221 is 1224411420031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 786848832025 + 513392312196 = 887045^2 + 716514^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300241144221 - 221 = 1300239047069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300241144261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650120572110 + 650120572111.

It is an arithmetic number, because the mean of its divisors is an integer number (650120572111).

Almost surely, 21300241144221 is an apocalyptic number.

It is an amenable number.

1300241144221 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300241144221 is an equidigital number, since it uses as much as digits as its factorization.

1300241144221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1300241144221 its reverse (1224411420031), we get a palindrome (2524652564252).

The spelling of 1300241144221 in words is "one trillion, three hundred billion, two hundred forty-one million, one hundred forty-four thousand, two hundred twenty-one".