Base | Representation |
---|---|
bin | 100110110000000… |
… | …0100100101110111 |
3 | 10100121122200212021 |
4 | 1031200010211313 |
5 | 10130331044142 |
6 | 333004534011 |
7 | 44135653132 |
oct | 11540044567 |
9 | 3317580767 |
10 | 1300253047 |
11 | 607a603a5 |
12 | 303551307 |
13 | 1794c6202 |
14 | c4989219 |
15 | 79240267 |
hex | 4d804977 |
1300253047 has 2 divisors, whose sum is σ = 1300253048. Its totient is φ = 1300253046.
The previous prime is 1300252981. The next prime is 1300253063. The reversal of 1300253047 is 7403520031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1300253047 - 215 = 1300220279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300254047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650126523 + 650126524.
It is an arithmetic number, because the mean of its divisors is an integer number (650126524).
Almost surely, 21300253047 is an apocalyptic number.
1300253047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300253047 is an equidigital number, since it uses as much as digits as its factorization.
1300253047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2520, while the sum is 25.
The square root of 1300253047 is about 36059.0217144060. The cubic root of 1300253047 is about 1091.4636922349.
Adding to 1300253047 its reverse (7403520031), we get a palindrome (8703773078).
It can be divided in two parts, 13002 and 53047, that added together give a square (66049 = 2572).
The spelling of 1300253047 in words is "one billion, three hundred million, two hundred fifty-three thousand, forty-seven".
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