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130031023343100 = 2235211311280999233
BaseRepresentation
bin11101100100001100110100…
…111101001100010111111100
3122001101211210120220101222020
4131210030310331030113330
5114020412013433434400
61140315232155520140
736250300655603055
oct3544146475142774
9561354716811866
10130031023343100
1138482935859060
1212700a72759050
135772b4696b439
14241776c4ad72c
151007612e652a0
hex764334f4c5fc

130031023343100 has 288 divisors, whose sum is σ = 423702061332480. Its totient is φ = 30503122944000.

The previous prime is 130031023343093. The next prime is 130031023343101. The reversal of 130031023343100 is 1343320130031.

It is a happy number.

It is a super-2 number, since 2×1300310233431002 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130031023343101) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1310311084 + ... + 1310410316.

It is an arithmetic number, because the mean of its divisors is an integer number (1471187712960).

Almost surely, 2130031023343100 is an apocalyptic number.

130031023343100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130031023343100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (211851030666240).

130031023343100 is an abundant number, since it is smaller than the sum of its proper divisors (293671037989380).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130031023343100 is a wasteful number, since it uses less digits than its factorization.

130031023343100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112101 (or 112094 counting only the distinct ones).

The product of its (nonzero) digits is 1944, while the sum is 24.

Adding to 130031023343100 its reverse (1343320130031), we get a palindrome (131374343473131).

The spelling of 130031023343100 in words is "one hundred thirty trillion, thirty-one billion, twenty-three million, three hundred forty-three thousand, one hundred".