Base | Representation |
---|---|
bin | 10010111011000000101… |
… | …000110000011101100011 |
3 | 11121022022222111101012111 |
4 | 102323000220300131203 |
5 | 132301014340024443 |
6 | 2433204411340151 |
7 | 162641641626055 |
oct | 22730050603543 |
9 | 4538288441174 |
10 | 1300312033123 |
11 | 461506275304 |
12 | 190013a51657 |
13 | 9580794931c |
14 | 46d14bb18d5 |
15 | 23c5650e69d |
hex | 12ec0a30763 |
1300312033123 has 2 divisors, whose sum is σ = 1300312033124. Its totient is φ = 1300312033122.
The previous prime is 1300312033121. The next prime is 1300312033169. The reversal of 1300312033123 is 3213302130031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1300312033123 - 21 = 1300312033121 is a prime.
It is a super-2 number, since 2×13003120331232 (a number of 25 digits) contains 22 as substring.
Together with 1300312033121, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1300312033094 and 1300312033103.
It is not a weakly prime, because it can be changed into another prime (1300312033121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650156016561 + 650156016562.
It is an arithmetic number, because the mean of its divisors is an integer number (650156016562).
Almost surely, 21300312033123 is an apocalyptic number.
1300312033123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300312033123 is an equidigital number, since it uses as much as digits as its factorization.
1300312033123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 1300312033123 its reverse (3213302130031), we get a palindrome (4513614163154).
The spelling of 1300312033123 in words is "one trillion, three hundred billion, three hundred twelve million, thirty-three thousand, one hundred twenty-three".
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