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130032333253 is a prime number
BaseRepresentation
bin111100100011010000…
…1111111000111000101
3110102122011202221111201
41321012201333013011
54112301234131003
6135422552102501
712252215411254
oct1710641770705
9412564687451
10130032333253
1150167953629
122124b694a31
13c3537b5834
1464178c479b
1535b0aedb1d
hex1e4687f1c5

130032333253 has 2 divisors, whose sum is σ = 130032333254. Its totient is φ = 130032333252.

The previous prime is 130032333229. The next prime is 130032333313. The reversal of 130032333253 is 352333230031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117644198049 + 12388135204 = 342993^2 + 111302^2 .

It is an emirp because it is prime and its reverse (352333230031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130032333253 - 221 = 130030236101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130032333553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016166626 + 65016166627.

It is an arithmetic number, because the mean of its divisors is an integer number (65016166627).

Almost surely, 2130032333253 is an apocalyptic number.

It is an amenable number.

130032333253 is a deficient number, since it is larger than the sum of its proper divisors (1).

130032333253 is an equidigital number, since it uses as much as digits as its factorization.

130032333253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14580, while the sum is 28.

Adding to 130032333253 its reverse (352333230031), we get a palindrome (482365563284).

The spelling of 130032333253 in words is "one hundred thirty billion, thirty-two million, three hundred thirty-three thousand, two hundred fifty-three".