Base | Representation |
---|---|
bin | 111100100011010000… |
… | …1111111001000000001 |
3 | 110102122011202221120221 |
4 | 1321012201333020001 |
5 | 4112301234131223 |
6 | 135422552103041 |
7 | 12252215411401 |
oct | 1710641771001 |
9 | 412564687527 |
10 | 130032333313 |
11 | 50167953683 |
12 | 2124b694a81 |
13 | c3537b587c |
14 | 64178c4801 |
15 | 35b0aedb5d |
hex | 1e4687f201 |
130032333313 has 2 divisors, whose sum is σ = 130032333314. Its totient is φ = 130032333312.
The previous prime is 130032333253. The next prime is 130032333341. The reversal of 130032333313 is 313333230031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116125555984 + 13906777329 = 340772^2 + 117927^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130032333313 is a prime.
It is not a weakly prime, because it can be changed into another prime (130032333373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016166656 + 65016166657.
It is an arithmetic number, because the mean of its divisors is an integer number (65016166657).
Almost surely, 2130032333313 is an apocalyptic number.
It is an amenable number.
130032333313 is a deficient number, since it is larger than the sum of its proper divisors (1).
130032333313 is an equidigital number, since it uses as much as digits as its factorization.
130032333313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4374, while the sum is 25.
Adding to 130032333313 its reverse (313333230031), we get a palindrome (443365563344).
The spelling of 130032333313 in words is "one hundred thirty billion, thirty-two million, three hundred thirty-three thousand, three hundred thirteen".
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