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130032552405101 is a prime number
BaseRepresentation
bin11101100100001110010000…
…000110000110100001101101
3122001101222202011002210201012
4131210032100012012201231
5114020423131403430401
61140320044020555005
736250353603451553
oct3544162006064155
9561358664083635
10130032552405101
113848354a988a65
121270121a852a65
13577302b697758
1424178755b9bd3
1510076a23008bb
hex76439018686d

130032552405101 has 2 divisors, whose sum is σ = 130032552405102. Its totient is φ = 130032552405100.

The previous prime is 130032552405061. The next prime is 130032552405127. The reversal of 130032552405101 is 101504255230031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128841455197225 + 1191097207876 = 11350835^2 + 1091374^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130032552405101 is a prime.

It is a super-2 number, since 2×1300325524051012 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130032582405101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016276202550 + 65016276202551.

It is an arithmetic number, because the mean of its divisors is an integer number (65016276202551).

Almost surely, 2130032552405101 is an apocalyptic number.

It is an amenable number.

130032552405101 is a deficient number, since it is larger than the sum of its proper divisors (1).

130032552405101 is an equidigital number, since it uses as much as digits as its factorization.

130032552405101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 32.

The spelling of 130032552405101 in words is "one hundred thirty trillion, thirty-two billion, five hundred fifty-two million, four hundred five thousand, one hundred one".