Base | Representation |
---|---|
bin | 111100100011010010… |
… | …0111111001101101111 |
3 | 110102122020020220212121 |
4 | 1321012210333031233 |
5 | 4112301434320421 |
6 | 135423021013411 |
7 | 12252225166306 |
oct | 1710644771557 |
9 | 412566226777 |
10 | 130033120111 |
11 | 50168340824 |
12 | 2124b9b4267 |
13 | c3539cca2b |
14 | 6417a4b43d |
15 | 35b0c06d41 |
hex | 1e4693f36f |
130033120111 has 2 divisors, whose sum is σ = 130033120112. Its totient is φ = 130033120110.
The previous prime is 130033120109. The next prime is 130033120121. The reversal of 130033120111 is 111021330031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130033120111 - 21 = 130033120109 is a prime.
It is a super-2 number, since 2×1300331201112 (a number of 23 digits) contains 22 as substring.
Together with 130033120109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130033120121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016560055 + 65016560056.
It is an arithmetic number, because the mean of its divisors is an integer number (65016560056).
Almost surely, 2130033120111 is an apocalyptic number.
130033120111 is a deficient number, since it is larger than the sum of its proper divisors (1).
130033120111 is an equidigital number, since it uses as much as digits as its factorization.
130033120111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 130033120111 its reverse (111021330031), we get a palindrome (241054450142).
The spelling of 130033120111 in words is "one hundred thirty billion, thirty-three million, one hundred twenty thousand, one hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •