Base | Representation |
---|---|
bin | 1011110100111001001010… |
… | …0100011111100110100000 |
3 | 1201001002212002011022201221 |
4 | 2331032102210133212200 |
5 | 3201021302202421102 |
6 | 43353351155504424 |
7 | 2511313342124521 |
oct | 275162244374640 |
9 | 51032762138657 |
10 | 13003325045152 |
11 | 4163751aa03a2 |
12 | 156016b2b8114 |
13 | 7342927c9360 |
14 | 32d515880848 |
15 | 1783a6535637 |
hex | bd39291f9a0 |
13003325045152 has 24 divisors (see below), whose sum is σ = 27569549736036. Its totient is φ = 6001534636032.
The previous prime is 13003325045149. The next prime is 13003325045189. The reversal of 13003325045152 is 25154052330031.
13003325045152 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 9141455498256 + 3861869546896 = 3023484^2 + 1965164^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15628996033 + ... + 15628996864.
Almost surely, 213003325045152 is an apocalyptic number.
It is an amenable number.
13003325045152 is an abundant number, since it is smaller than the sum of its proper divisors (14566224690884).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13003325045152 is a wasteful number, since it uses less digits than its factorization.
13003325045152 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31257992920 (or 31257992912 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 13003325045152 its reverse (25154052330031), we get a palindrome (38157377375183).
The spelling of 13003325045152 in words is "thirteen trillion, three billion, three hundred twenty-five million, forty-five thousand, one hundred fifty-two".
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