130040314081 has 2 divisors, whose sum is σ = 130040314082. Its totient is φ = 130040314080.

The previous prime is 130040314067. The next prime is 130040314141. The reversal of 130040314081 is 180413040031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120628403856 + 9411910225 = 347316^2 + 97015^2 .

It is a cyclic number.

It is not a de Polignac number, because 130040314081 - 2⁹ = 130040313569 is a prime.

It is a super-2 number, since 2×130040314081² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130040314181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65020157040 + 65020157041.

It is an arithmetic number, because the mean of its divisors is an integer number (65020157041).

Almost surely, 2^130040314081 is an apocalyptic number.

It is an amenable number.

130040314081 is a deficient number, since it is larger than the sum of its proper divisors (1).

130040314081 is an equidigital number, since it uses as much as digits as its factorization.

130040314081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

The spelling of 130040314081 in words is "one hundred thirty billion, forty million, three hundred fourteen thousand, eighty-one".