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130040314141 is a prime number
BaseRepresentation
bin111100100011100000…
…0011011100100011101
3110102122201210102020011
41321013000123210131
54112310310023031
6135423435123221
712252343301203
oct1710700334435
9412581712204
10130040314141
1150171404801
12212522a3511
13c35534b35a
1464189a1073
1535b16786b1
hex1e4701b91d

130040314141 has 2 divisors, whose sum is σ = 130040314142. Its totient is φ = 130040314140.

The previous prime is 130040314081. The next prime is 130040314147. The reversal of 130040314141 is 141413040031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65042851225 + 64997462916 = 255035^2 + 254946^2 .

It is a cyclic number.

It is not a de Polignac number, because 130040314141 - 29 = 130040313629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130040314147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65020157070 + 65020157071.

It is an arithmetic number, because the mean of its divisors is an integer number (65020157071).

Almost surely, 2130040314141 is an apocalyptic number.

It is an amenable number.

130040314141 is a deficient number, since it is larger than the sum of its proper divisors (1).

130040314141 is an equidigital number, since it uses as much as digits as its factorization.

130040314141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 130040314141 its reverse (141413040031), we get a palindrome (271453354172).

The spelling of 130040314141 in words is "one hundred thirty billion, forty million, three hundred fourteen thousand, one hundred forty-one".