Base | Representation |
---|---|
bin | 111100100011100010… |
… | …0010001111001110100 |
3 | 110102122210200200021220 |
4 | 1321013010101321310 |
5 | 4112311034314444 |
6 | 135423512510340 |
7 | 12252355002636 |
oct | 1710704217164 |
9 | 412583620256 |
10 | 130041323124 |
11 | 50171a33879 |
12 | 212526ab3b0 |
13 | c35561269b |
14 | 6418b84a56 |
15 | 35b17c7619 |
hex | 1e47111e74 |
130041323124 has 48 divisors (see below), whose sum is σ = 318192813120. Its totient is φ = 41279051520.
The previous prime is 130041323077. The next prime is 130041323129. The reversal of 130041323124 is 421323140031.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 130041323094 and 130041323103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130041323129) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2534062 + ... + 2584869.
It is an arithmetic number, because the mean of its divisors is an integer number (6629016940).
Almost surely, 2130041323124 is an apocalyptic number.
It is an amenable number.
130041323124 is an abundant number, since it is smaller than the sum of its proper divisors (188151489996).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130041323124 is a wasteful number, since it uses less digits than its factorization.
130041323124 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5119040 (or 5119038 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 130041323124 its reverse (421323140031), we get a palindrome (551364463155).
The spelling of 130041323124 in words is "one hundred thirty billion, forty-one million, three hundred twenty-three thousand, one hundred twenty-four".
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