Base | Representation |
---|---|
bin | 100110110000010… |
… | …1110001010110000 |
3 | 10100121222100110120 |
4 | 1031200232022300 |
5 | 10130402021334 |
6 | 333012330240 |
7 | 44140262463 |
oct | 11540561260 |
9 | 3317870416 |
10 | 1300423344 |
11 | 608067340 |
12 | 303613980 |
13 | 17955588c |
14 | c49d12da |
15 | 79275949 |
hex | 4d82e2b0 |
1300423344 has 80 divisors (see below), whose sum is σ = 3669943680. Its totient is φ = 393518080.
The previous prime is 1300423343. The next prime is 1300423373. The reversal of 1300423344 is 4433240031.
It is a super-2 number, since 2×13004233442 = 3382201747240284672, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is not an unprimeable number, because it can be changed into a prime (1300423343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 536824 + ... + 539240.
It is an arithmetic number, because the mean of its divisors is an integer number (45874296).
Almost surely, 21300423344 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1300423344, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1834971840).
1300423344 is an abundant number, since it is smaller than the sum of its proper divisors (2369520336).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300423344 is a wasteful number, since it uses less digits than its factorization.
1300423344 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3458 (or 3452 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 24.
The square root of 1300423344 is about 36061.3830017652. The cubic root of 1300423344 is about 1091.5113406211.
Adding to 1300423344 its reverse (4433240031), we get a palindrome (5733663375).
It can be divided in two parts, 130042 and 3344, that added together give a triangular number (133386 = T516).
The spelling of 1300423344 in words is "one billion, three hundred million, four hundred twenty-three thousand, three hundred forty-four".
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