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1300424014909 is a prime number
BaseRepresentation
bin10010111011000111010…
…011111011110000111101
311121022121210012122100001
4102323013103323300331
5132301232021434114
62433223451434301
7162644501513425
oct22730723736075
94538553178301
101300424014909
114615634aa938
12190045455991
1395824bc6736
1446d25a01485
1523c6127e374
hex12ec74fbc3d

1300424014909 has 2 divisors, whose sum is σ = 1300424014910. Its totient is φ = 1300424014908.

The previous prime is 1300424014891. The next prime is 1300424014943. The reversal of 1300424014909 is 9094104240031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 918141490809 + 382282524100 = 958197^2 + 618290^2 .

It is an emirp because it is prime and its reverse (9094104240031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1300424014909 - 211 = 1300424012861 is a prime.

It is a super-2 number, since 2×13004240149092 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300424014009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650212007454 + 650212007455.

It is an arithmetic number, because the mean of its divisors is an integer number (650212007455).

Almost surely, 21300424014909 is an apocalyptic number.

It is an amenable number.

1300424014909 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300424014909 is an equidigital number, since it uses as much as digits as its factorization.

1300424014909 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 37.

The spelling of 1300424014909 in words is "one trillion, three hundred billion, four hundred twenty-four million, fourteen thousand, nine hundred nine".