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1300424014943 is a prime number
BaseRepresentation
bin10010111011000111010…
…011111011110001011111
311121022121210012122101022
4102323013103323301133
5132301232021434233
62433223451434355
7162644501513504
oct22730723736137
94538553178338
101300424014943
114615634aa969
121900454559bb
1395824bc6761
1446d25a014ab
1523c6127e398
hex12ec74fbc5f

1300424014943 has 2 divisors, whose sum is σ = 1300424014944. Its totient is φ = 1300424014942.

The previous prime is 1300424014909. The next prime is 1300424015029. The reversal of 1300424014943 is 3494104240031.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1300424014943 is a prime.

It is a super-2 number, since 2×13004240149432 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300429014943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650212007471 + 650212007472.

It is an arithmetic number, because the mean of its divisors is an integer number (650212007472).

Almost surely, 21300424014943 is an apocalyptic number.

1300424014943 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300424014943 is an equidigital number, since it uses as much as digits as its factorization.

1300424014943 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 35.

Adding to 1300424014943 its reverse (3494104240031), we get a palindrome (4794528254974).

The spelling of 1300424014943 in words is "one trillion, three hundred billion, four hundred twenty-four million, fourteen thousand, nine hundred forty-three".