Base | Representation |
---|---|
bin | 100110110000011… |
… | …0000100011011000 |
3 | 10100121222211212100 |
4 | 1031200300203120 |
5 | 10130402324422 |
6 | 333012443400 |
7 | 44140333116 |
oct | 11540604330 |
9 | 3317884770 |
10 | 1300433112 |
11 | 608073710 |
12 | 303619560 |
13 | 17955a164 |
14 | c49d4ab6 |
15 | 792787ac |
hex | 4d8308d8 |
1300433112 has 192 divisors, whose sum is σ = 4094064000. Its totient is φ = 368755200.
The previous prime is 1300433077. The next prime is 1300433129. The reversal of 1300433112 is 2113340031.
It is a super-2 number, since 2×13004331122 = 3382252557572009088, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1338787 + ... + 1339757.
It is an arithmetic number, because the mean of its divisors is an integer number (21323250).
Almost surely, 21300433112 is an apocalyptic number.
1300433112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1300433112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2047032000).
1300433112 is an abundant number, since it is smaller than the sum of its proper divisors (2793630888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300433112 is a wasteful number, since it uses less digits than its factorization.
1300433112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1102 (or 1095 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
The square root of 1300433112 is about 36061.5184372483. The cubic root of 1300433112 is about 1091.5140735404.
Adding to 1300433112 its reverse (2113340031), we get a palindrome (3413773143).
The spelling of 1300433112 in words is "one billion, three hundred million, four hundred thirty-three thousand, one hundred twelve".
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