Base | Representation |
---|---|
bin | 1011110100111101001101… |
… | …0000111011000111101111 |
3 | 1201001012122201111210101001 |
4 | 2331033103100323013233 |
5 | 3201031013032342111 |
6 | 43354051011301131 |
7 | 2511352261564552 |
oct | 275172320730757 |
9 | 51035581453331 |
10 | 13004410434031 |
11 | 41641597360a5 |
12 | 15604128aa7a7 |
13 | 7344066326b3 |
14 | 32d5b9a98699 |
15 | 17841b9821c1 |
hex | bd3d343b1ef |
13004410434031 has 2 divisors, whose sum is σ = 13004410434032. Its totient is φ = 13004410434030.
The previous prime is 13004410433951. The next prime is 13004410434097. The reversal of 13004410434031 is 13043401440031.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (13043401440031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13004410434031 - 235 = 12970050695663 is a prime.
It is a super-2 number, since 2×130044104340312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13004410434131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502205217015 + 6502205217016.
It is an arithmetic number, because the mean of its divisors is an integer number (6502205217016).
Almost surely, 213004410434031 is an apocalyptic number.
13004410434031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13004410434031 is an equidigital number, since it uses as much as digits as its factorization.
13004410434031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 13004410434031 its reverse (13043401440031), we get a palindrome (26047811874062).
The spelling of 13004410434031 in words is "thirteen trillion, four billion, four hundred ten million, four hundred thirty-four thousand, thirty-one".
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