130044220123 has 2 divisors, whose sum is σ = 130044220124. Its totient is φ = 130044220122.

The previous prime is 130044220003. The next prime is 130044220171. The reversal of 130044220123 is 321022440031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130044220123 is a prime.

It is a super-2 number, since 2×130044220123² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130044220094 and 130044220103.

It is not a weakly prime, because it can be changed into another prime (130044220193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65022110061 + 65022110062.

It is an arithmetic number, because the mean of its divisors is an integer number (65022110062).

Almost surely, 2^130044220123 is an apocalyptic number.

130044220123 is a deficient number, since it is larger than the sum of its proper divisors (1).

130044220123 is an equidigital number, since it uses as much as digits as its factorization.

130044220123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 130044220123 its reverse (321022440031), we get a palindrome (451066660154).

The spelling of 130044220123 in words is "one hundred thirty billion, forty-four million, two hundred twenty thousand, one hundred twenty-three".