Base | Representation |
---|---|
bin | 111100100011100111… |
… | …1010101001100001011 |
3 | 110102200000010212021221 |
4 | 1321013033111030023 |
5 | 4112312310021141 |
6 | 135424054542511 |
7 | 12252421430065 |
oct | 1710717251413 |
9 | 412600125257 |
10 | 130044220171 |
11 | 50173632428 |
12 | 21253667a37 |
13 | c3560b8208 |
14 | 64192da735 |
15 | 35b1b9abd1 |
hex | 1e473d530b |
130044220171 has 2 divisors, whose sum is σ = 130044220172. Its totient is φ = 130044220170.
The previous prime is 130044220123. The next prime is 130044220193. The reversal of 130044220171 is 171022440031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130044220171 - 219 = 130043695883 is a prime.
It is a super-2 number, since 2×1300442201712 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130044220871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65022110085 + 65022110086.
It is an arithmetic number, because the mean of its divisors is an integer number (65022110086).
Almost surely, 2130044220171 is an apocalyptic number.
130044220171 is a deficient number, since it is larger than the sum of its proper divisors (1).
130044220171 is an equidigital number, since it uses as much as digits as its factorization.
130044220171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
The spelling of 130044220171 in words is "one hundred thirty billion, forty-four million, two hundred twenty thousand, one hundred seventy-one".
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