130044220193 has 2 divisors, whose sum is σ = 130044220194. Its totient is φ = 130044220192.

The previous prime is 130044220171. The next prime is 130044220219. The reversal of 130044220193 is 391022440031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130027311649 + 16908544 = 360593^2 + 4112^2 .

It is a cyclic number.

It is not a de Polignac number, because 130044220193 - 2¹² = 130044216097 is a prime.

It is a super-2 number, since 2×130044220193² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130044220123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65022110096 + 65022110097.

It is an arithmetic number, because the mean of its divisors is an integer number (65022110097).

Almost surely, 2^130044220193 is an apocalyptic number.

It is an amenable number.

130044220193 is a deficient number, since it is larger than the sum of its proper divisors (1).

130044220193 is an equidigital number, since it uses as much as digits as its factorization.

130044220193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

The spelling of 130044220193 in words is "one hundred thirty billion, forty-four million, two hundred twenty thousand, one hundred ninety-three".