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13004440517 is a prime number
BaseRepresentation
bin11000001110010000…
…00000001111000101
31020120022011000201002
430013020000033011
5203113114044032
65550230143045
7640155630515
oct140710001705
936508130632
1013004440517
115573738702
12262b1b1a85
1312c3297c23
148b51a3845
15511a2c862
hex3072003c5

13004440517 has 2 divisors, whose sum is σ = 13004440518. Its totient is φ = 13004440516.

The previous prime is 13004440499. The next prime is 13004440543. The reversal of 13004440517 is 71504440031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7179850756 + 5824589761 = 84734^2 + 76319^2 .

It is a cyclic number.

It is not a de Polignac number, because 13004440517 - 212 = 13004436421 is a prime.

It is a super-3 number, since 3×130044405173 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13004440517.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13004440567) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502220258 + 6502220259.

It is an arithmetic number, because the mean of its divisors is an integer number (6502220259).

Almost surely, 213004440517 is an apocalyptic number.

It is an amenable number.

13004440517 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004440517 is an equidigital number, since it uses as much as digits as its factorization.

13004440517 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 29.

Adding to 13004440517 its reverse (71504440031), we get a palindrome (84508880548).

The spelling of 13004440517 in words is "thirteen billion, four million, four hundred forty thousand, five hundred seventeen".