Search a number
-
+
130047539 is a prime number
BaseRepresentation
bin1111100000001…
…01111000110011
3100001201002200112
413300011320303
5231243010124
620523211535
73136246226
oct760057063
9301632615
10130047539
1167454706
1237676bab
1320c3430b
14133b35bd
15b63c90e
hex7c05e33

130047539 has 2 divisors, whose sum is σ = 130047540. Its totient is φ = 130047538.

The previous prime is 130047503. The next prime is 130047553. The reversal of 130047539 is 935740031.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (935740031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130047539 - 28 = 130047283 is a prime.

It is a super-3 number, since 3×1300475393 (a number of 25 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130047439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65023769 + 65023770.

It is an arithmetic number, because the mean of its divisors is an integer number (65023770).

Almost surely, 2130047539 is an apocalyptic number.

130047539 is a deficient number, since it is larger than the sum of its proper divisors (1).

130047539 is an equidigital number, since it uses as much as digits as its factorization.

130047539 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11340, while the sum is 32.

The square root of 130047539 is about 11403.8387834974. The cubic root of 130047539 is about 506.6414438525.

The spelling of 130047539 in words is "one hundred thirty million, forty-seven thousand, five hundred thirty-nine".