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13005112440 = 23354753139313
BaseRepresentation
bin11000001110010101…
…00100010001111000
31020120100102011102010
430013022210101320
5203113302044230
65550252405520
7640164426465
oct140712442170
936510364363
1013005112440
115574057511
12262b4768a0
1312c3471a08
148b52da66c
15511b119b0
hex3072a4478

13005112440 has 256 divisors, whose sum is σ = 41019955200. Its totient is φ = 3295678464.

The previous prime is 13005112429. The next prime is 13005112453. The reversal of 13005112440 is 4421150031.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 41549724 + ... + 41550036.

It is an arithmetic number, because the mean of its divisors is an integer number (160234200).

Almost surely, 213005112440 is an apocalyptic number.

13005112440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13005112440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20509977600).

13005112440 is an abundant number, since it is smaller than the sum of its proper divisors (28014842760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13005112440 is a wasteful number, since it uses less digits than its factorization.

13005112440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 566 (or 562 counting only the distinct ones).

The product of its (nonzero) digits is 480, while the sum is 21.

Adding to 13005112440 its reverse (4421150031), we get a palindrome (17426262471).

The spelling of 13005112440 in words is "thirteen billion, five million, one hundred twelve thousand, four hundred forty".