Base | Representation |
---|---|
bin | 10010111011001110010… |
… | …110000011101100111111 |
3 | 11121022221000020112012221 |
4 | 102323032112003230333 |
5 | 132302002223342343 |
6 | 2433243304510211 |
7 | 162650433464056 |
oct | 22731626035477 |
9 | 4538830215187 |
10 | 1300542012223 |
11 | 461614073a83 |
12 | 190078a7b367 |
13 | 9584349bc2c |
14 | 46d3755939d |
15 | 23c6b7db5ed |
hex | 12ece583b3f |
1300542012223 has 2 divisors, whose sum is σ = 1300542012224. Its totient is φ = 1300542012222.
The previous prime is 1300542012179. The next prime is 1300542012239. The reversal of 1300542012223 is 3222102450031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1300542012223 - 225 = 1300508457791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300542013223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650271006111 + 650271006112.
It is an arithmetic number, because the mean of its divisors is an integer number (650271006112).
Almost surely, 21300542012223 is an apocalyptic number.
1300542012223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300542012223 is an equidigital number, since it uses as much as digits as its factorization.
1300542012223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 1300542012223 its reverse (3222102450031), we get a palindrome (4522644462254).
The spelling of 1300542012223 in words is "one trillion, three hundred billion, five hundred forty-two million, twelve thousand, two hundred twenty-three".
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