Base | Representation |
---|---|
bin | 111100100011111110… |
… | …0011000100101110101 |
3 | 110102200211100220010112 |
4 | 1321013330120211311 |
5 | 4112323320434311 |
6 | 135425200032405 |
7 | 12252624006551 |
oct | 1710774304565 |
9 | 412624326115 |
10 | 130056030581 |
11 | 5017a2697a4 |
12 | 21257602705 |
13 | c358691b19 |
14 | 641aad2861 |
15 | 35b2c3028b |
hex | 1e47f18975 |
130056030581 has 2 divisors, whose sum is σ = 130056030582. Its totient is φ = 130056030580.
The previous prime is 130056030551. The next prime is 130056030647. The reversal of 130056030581 is 185030650031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99771329956 + 30284700625 = 315866^2 + 174025^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130056030581 is a prime.
It is a super-2 number, since 2×1300560305812 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130056030551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65028015290 + 65028015291.
It is an arithmetic number, because the mean of its divisors is an integer number (65028015291).
Almost surely, 2130056030581 is an apocalyptic number.
It is an amenable number.
130056030581 is a deficient number, since it is larger than the sum of its proper divisors (1).
130056030581 is an equidigital number, since it uses as much as digits as its factorization.
130056030581 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 32.
The spelling of 130056030581 in words is "one hundred thirty billion, fifty-six million, thirty thousand, five hundred eighty-one".
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