Base | Representation |
---|---|
bin | 11101100100111011111101… |
… | …100100001101110000111110 |
3 | 122001120200102201010200022202 |
4 | 131210323331210031300332 |
5 | 114022224141203441440 |
6 | 1140354402202311502 |
7 | 36254042101266251 |
oct | 3544737544156076 |
9 | 561520381120282 |
10 | 130081633655870 |
11 | 384a2346a83126 |
12 | 1270a837ab8592 |
13 | 5777850ca7a80 |
14 | 2419dadcad098 |
15 | 1008ac61b3615 |
hex | 764efd90dc3e |
130081633655870 has 32 divisors (see below), whose sum is σ = 252168922117728. Its totient is φ = 48028107673728.
The previous prime is 130081633655843. The next prime is 130081633655921. The reversal of 130081633655870 is 78556336180031.
It is a Smith number, since the sum of its digits (56) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18104009 + ... + 24247028.
It is an arithmetic number, because the mean of its divisors is an integer number (7880278816179).
Almost surely, 2130081633655870 is an apocalyptic number.
130081633655870 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130081633655870 is a deficient number, since it is larger than the sum of its proper divisors (122087288461858).
130081633655870 is a wasteful number, since it uses less digits than its factorization.
130081633655870 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42374684.
The product of its (nonzero) digits is 10886400, while the sum is 56.
The spelling of 130081633655870 in words is "one hundred thirty trillion, eighty-one billion, six hundred thirty-three million, six hundred fifty-five thousand, eight hundred seventy".
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