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130102234333 is a prime number
BaseRepresentation
bin111100100101010110…
…0101000110011011101
3110102211001022021202121
41321022230220303131
54112422132444313
6135433530222541
712254024513431
oct1711254506335
9412731267677
10130102234333
11501a3357315
122126ab84a51
13c36511b316
146422cbc9c1
1535b6d0a28d
hex1e4ab28cdd

130102234333 has 2 divisors, whose sum is σ = 130102234334. Its totient is φ = 130102234332.

The previous prime is 130102234321. The next prime is 130102234343. The reversal of 130102234333 is 333432201031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127782656089 + 2319578244 = 357467^2 + 48162^2 .

It is an emirp because it is prime and its reverse (333432201031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130102234333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130102234298 and 130102234307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130102234303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65051117166 + 65051117167.

It is an arithmetic number, because the mean of its divisors is an integer number (65051117167).

Almost surely, 2130102234333 is an apocalyptic number.

It is an amenable number.

130102234333 is a deficient number, since it is larger than the sum of its proper divisors (1).

130102234333 is an equidigital number, since it uses as much as digits as its factorization.

130102234333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 130102234333 its reverse (333432201031), we get a palindrome (463534435364).

The spelling of 130102234333 in words is "one hundred thirty billion, one hundred two million, two hundred thirty-four thousand, three hundred thirty-three".